Published by:
CGP EDU Academic Team
Published on: September 13, 2026
A body of mass 5 kg is acted upon by a variable force. The force varies with the distance covered by the body. What is the speed of the body when the body has covered 25 m? Assume that the body starts from rest.

Text Solution
Verified by ExpertsThe correct answer is:
B
Step 1: Identify the force acting on the body from the graph. For the first 25 m, the force is constant at 10 N.
Step 2: Use Newton's second law, which states that Force = mass \( \times \) acceleration (F = ma). Here, m = 5 kg and F = 10 N.
Therefore, acceleration (a) = \( \frac{F}{m} = \frac{10 \text{ N}}{5 \text{ kg}} = 2 \text{ m/s}^2 \).
Step 3: Apply the kinematic equation for motion starting from rest: \( v^2 = u^2 + 2as \), where u = initial velocity (0 m/s), a = acceleration (2 m/s²), and s = distance covered (25 m).
Plugging in the values gives: \( v^2 = 0 + 2 \times 2 \times 25 = 100 \).
Step 4: Taking the square root: \( v = \sqrt{100} = 10 \text{ m/s} \).
Therefore, the speed of the body when it has covered 25 m is 10 m/s.
Step 2: Use Newton's second law, which states that Force = mass \( \times \) acceleration (F = ma). Here, m = 5 kg and F = 10 N.
Therefore, acceleration (a) = \( \frac{F}{m} = \frac{10 \text{ N}}{5 \text{ kg}} = 2 \text{ m/s}^2 \).
Step 3: Apply the kinematic equation for motion starting from rest: \( v^2 = u^2 + 2as \), where u = initial velocity (0 m/s), a = acceleration (2 m/s²), and s = distance covered (25 m).
Plugging in the values gives: \( v^2 = 0 + 2 \times 2 \times 25 = 100 \).
Step 4: Taking the square root: \( v = \sqrt{100} = 10 \text{ m/s} \).
Therefore, the speed of the body when it has covered 25 m is 10 m/s.
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